I’m stuck on this problem and don’t even know where to start on it.any help would be great. Thanks.
There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 12 cm. When the cylinder is rotating at 2.4 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall.
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Centripetal acceleration is just Ac=v^2/r. The circumference is (2)(pi)(r) which is 2(3.14)(12) which equals 75.36 cm. So your velocity is 2.4(75.36) cm/s. so Ac= 2.4(75.36)/ 12 and that is about 15 cm^2/s. And the direction is always towards the centre of the circle.