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	<title>Comments on: Help. I need the width of a round room that totals 675 Sq. FT.</title>
	<atom:link href="http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/feed/" rel="self" type="application/rss+xml" />
	<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/</link>
	<description>Kitchen-Appliances-Pro.com</description>
	<pubDate>Sat, 19 May 2012 04:33:20 +0000</pubDate>
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		<title>By: rohan</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-212</link>
		<dc:creator>rohan</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-212</guid>
		<description>if its round, it cnt hv width,

it has a radius

wht u sayin totals 675 sq fts, so did u calcuate is by pi* radius *(power 2).</description>
		<content:encoded><![CDATA[<p>if its round, it cnt hv width,</p>
<p>it has a radius</p>
<p>wht u sayin totals 675 sq fts, so did u calcuate is by pi* radius *(power 2).</p>
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		<title>By: Dave</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-213</link>
		<dc:creator>Dave</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-213</guid>
		<description>Area = pi * r²

r = sqrt(Area/pi)

r = sqrt(675/pi)

width = 2*r

width = 2*sqrt(675/pi) ~~ 29.316150714175195295183077370301</description>
		<content:encoded><![CDATA[<p>Area = pi * r²</p>
<p>r = sqrt(Area/pi)</p>
<p>r = sqrt(675/pi)</p>
<p>width = 2*r</p>
<p>width = 2*sqrt(675/pi) ~~ 29.316150714175195295183077370301</p>
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		<title>By: Tommy12oz</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-214</link>
		<dc:creator>Tommy12oz</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-214</guid>
		<description>area of room= pi * radius^2
pi*r^2=675
r^2=214.859
r=14.6581
width of room=2*r
WIDTH OF ROOM=29.31 APPROXIMATE</description>
		<content:encoded><![CDATA[<p>area of room= pi * radius^2<br />
pi*r^2=675<br />
r^2=214.859<br />
r=14.6581<br />
width of room=2*r<br />
WIDTH OF ROOM=29.31 APPROXIMATE</p>
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		<title>By: Wazeem A</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-215</link>
		<dc:creator>Wazeem A</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-215</guid>
		<description>By width u mean diameter right

area = 675 = pi(radius)^2
        so radius=sqrt(675/pi)
        so width of room= 2*radius which comes to be about 29.2</description>
		<content:encoded><![CDATA[<p>By width u mean diameter right</p>
<p>area = 675 = pi(radius)^2<br />
        so radius=sqrt(675/pi)<br />
        so width of room= 2*radius which comes to be about 29.2</p>
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		<title>By: rwbblb46</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-216</link>
		<dc:creator>rwbblb46</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-216</guid>
		<description>A=pi*r^2  

r^2=A/pi =675/3.14=214.97

take square root  Ans. 14.66 radius</description>
		<content:encoded><![CDATA[<p>A=pi*r^2  </p>
<p>r^2=A/pi =675/3.14=214.97</p>
<p>take square root  Ans. 14.66 radius</p>
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		<title>By: amber_socci</title>
		<link>http://kitchen-appliances-pro.com/2008/04/28/help-i-need-the-width-of-a-round-room-that-totals-675-sq-ft/#comment-217</link>
		<dc:creator>amber_socci</dc:creator>
		<pubDate>Tue, 30 Nov 1999 00:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://answers.yahoo.com/question/?qid=20061022093429AA9RriL#comment-217</guid>
		<description>well the area of a circle is a=pi*r^2
so 675ft^2= 3.14*r^2
215=r^2
r= ~14.66

If you are creating this problem you may want to make it so that the students get a clear number, not .66. just a suggestion.</description>
		<content:encoded><![CDATA[<p>well the area of a circle is a=pi*r^2<br />
so 675ft^2= 3.14*r^2<br />
215=r^2<br />
r= ~14.66</p>
<p>If you are creating this problem you may want to make it so that the students get a clear number, not .66. just a suggestion.</p>
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